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Clean Architecture Toolkit is a clean, modular architecture foundation for .NET applications. It embraces SOLID principles and focuses on maintainability, testability, and scalability through clear boundaries and pluggable design. |
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| HOME | MODULE OVERVIEW | DEMO | CAT.EXTENSIONS | |
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Code Reference
» Cat.ServiceCollection.Extensions Assembly » Cat.ServiceCollection.Extensions Namespace » ServiceCollectionExtensions Class
ServiceCollectionExtensions.HasRegistrationFor Method
| Overloads | |
|---|---|
| HasRegistrationFor(this IServiceCollection, Type) | Checks whether the given service type is already registered in the service collection. An open generic type (such as typeof(IRepository<>)) matches any registration for that generic definition. |
| HasRegistrationFor<TService>(this IServiceCollection) | Checks whether TService is already registered in the service collection. |
ServiceCollectionExtensions.HasRegistrationFor(this IServiceCollection, Type) Method
Checks whether the given service type is already registered in the service collection. An open generic type
(such as typeof(IRepository<>)) matches any registration for that generic definition.
public static bool HasRegistrationFor(this Microsoft.Extensions.DependencyInjection.IServiceCollection services, System.Type serviceType);
Parameters
services Microsoft.Extensions.DependencyInjection.IServiceCollection
The service collection to check.
serviceType System.Type
The service type to look for.
Returns
System.Boolean
true if a matching registration exists.
ServiceCollectionExtensions.HasRegistrationFor<TService>(this IServiceCollection) Method
Checks whether TService is already registered in the service collection.
public static bool HasRegistrationFor<TService>(this Microsoft.Extensions.DependencyInjection.IServiceCollection services);
Type parameters
TService
The service type to look for.
Parameters
services Microsoft.Extensions.DependencyInjection.IServiceCollection
The service collection to check.
Returns
System.Boolean
true if a registration for TService exists.